Foundation November 2022 Paper 3 Q21
21 Make \(a\) the subject of the formula \(\quad p = 3a - 9\) (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(a = \dfrac{p+9}{3}\) | M1 | for correct first step to rearrange eg \(\;p + 9 = 3a - 9 + 9\;\) or \(\;\dfrac{p}{3} = \dfrac{3a - 9}{3}\;\) oe or answer ambiguously shown eg \(\;a = p + 9 \div 3\) or given as \(\dfrac{p+9}{3}\) oe |
| A1 | oe |
Additional guidance
May be seen in different equivalent forms but must be carried out, not just intention seen.