AS June 2018 Q4

EdexcelCurrent spec13 marksVariable Force & Kinematics

4. A particle, \(P\), moves on the \(x\)-axis. At time \(t\) seconds, \(t \geqslant 0\), the velocity of \(P\) is \(v\ \text{m s}^{-1}\) in the direction of \(x\) increasing and the acceleration of \(P\) is \(a\ \text{m s}^{-2}\) in the direction of \(x\) increasing.

When \(t = 0\) the particle is at rest at the origin \(O\).

Given that \(a = \dfrac{5}{2}(5 - v)\)

(a) show that \(v = 5\left(1 - \mathrm{e}^{-2.5t}\right)\) (5)
(b) state the limiting value of \(v\) as \(t\) increases. (1)

At the instant when \(v = 2.5\), the particle is \(d\) metres from \(O\).

(c) Show that \(d = 2\ln 2 - 1\) (7)