A2 June 2019 Q1
1.

Figure 1 represents the plan of part of a smooth horizontal floor, where \(W_1\) and \(W_2\) are two fixed parallel vertical walls. The walls are 3 metres apart.
A particle lies at rest at a point \(O\) on the floor between the two walls, where the point \(O\) is \(d\) metres, \(0 \lt d \leqslant 3\), from \(W_1\)
At time \(t = 0\), the particle is projected from \(O\) towards \(W_1\) with speed \(u\ \text{m s}^{-1}\) in a direction perpendicular to the walls.
The coefficient of restitution between the particle and each wall is \(\dfrac{2}{3}\)
The particle returns to \(O\) at time \(t = T\) seconds, having bounced off each wall once.
The value of \(u\) is fixed, the particle still hits each wall once but the value of \(d\) can now vary.
| Scheme | Marks | AO |
|---|---|---|
| Speed after first impact \(= \tfrac{2}{3}u\) | B1 | 3.4 |
| Speed after second impact \(= \tfrac{4}{9}u\) | B1 | 3.4 |
| Correct method for total time | M1 | 2.1 |
| \(T = \dfrac{d}{u} + \dfrac{3}{\frac{2}{3}u} + \dfrac{3 - d}{\frac{4}{9}u}\) | A1ft A1ft | 1.1b 1.1b |
| \(= \dfrac{4d + 18 + 27 - 9d}{4u} = \dfrac{45 - 5d}{4u}\) * | A1* | 2.2a |
| (6) |
Notes
B1: Correct use of impact law, seen or implied. Allow +/-
B1: Correct use of impact law a second time, seen or implied. Allow +/-
M1: Use of \(t = \dfrac{d}{v}\) or equivalent for at least 2 of the 3 parts added
A1ft: Unsimplified expression for \(T\) with all 3 terms and at most one error. Follow their speeds.
A1ft: Correct unsimplified expression for \(T\). Follow their speeds
A1*: Obtain given answer from correct working
| Scheme | Marks | AO |
|---|---|---|
| B1 | 2.4 |
| i.e. \(d = 3\), least \(T = \dfrac{30}{4u} = \dfrac{15}{2u}\) | B1 | 2.2a |
| (2) | ||
| (8 marks) |
Notes
B1: Correct reasoning
B1: Correct answer only. Any equivalent form. \(\left(\dfrac{7.5}{u}\right)\)