A2 June 2022 Q5
5. A standard transportation problem is described in the linear programming formulation below.
Let \(x_{ij}\) be the number of units transported from \(i\) to \(j\)
where \(i \in \{\text{A, B, C, D}\}\)
\(\qquad j \in \{\text{R, S, T}\}\) and \(x_{ij} \geqslant 0\)
Minimise \(P = 23x_{\text{AR}} + 17x_{\text{AS}} + 24x_{\text{AT}} + 15x_{\text{BR}} + 29x_{\text{BS}} + 32x_{\text{BT}}\)
\(\qquad\qquad + 25x_{\text{CR}} + 25x_{\text{CS}} + 27x_{\text{CT}} + 19x_{\text{DR}} + 20x_{\text{DS}} + 25x_{\text{DT}}\)
subject to
\[\begin{aligned} \sum x_{\text{A}j} &\leqslant 34 \\ \sum x_{\text{B}j} &\leqslant 27 \\ \sum x_{\text{C}j} &\leqslant 41 \\ \sum x_{\text{D}j} &\leqslant 18 \\ \sum x_{i\text{R}} &\geqslant 44 \\ \sum x_{i\text{S}} &\geqslant 37 \\ \sum x_{i\text{T}} &\geqslant k \end{aligned}\]Given that the problem is balanced,
- shadow costs
- improvement indices
- entering cell and exiting cell.
| Scheme | Marks | AO |
|---|---|---|
| \(k = 39\) | B1 | 2.2a |
| (1) |
Notes
B1: CAO
| Scheme | Marks | AO |
|---|---|---|
| To ensure that the total amount transported to destination R from the four supply points cannot be less than the demand of 44 | B2, 1, 0 | 2.4 2.4 |
| (2) |
Notes
B1: Partial correct reasoning – must include at least two of ‘destination R’, ‘supply points’, ‘cannot be less’/’must be at least’, ‘demand of 44’ oe (do not accept ‘greater than or equal to’)
B1: Fully correct reasoning – all points covered as stated above. No incorrect statement.
| Scheme | Marks | AO | ||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| B1 | 1.1b | ||||||||||||||||||||
| 2942 | B1 | 2.2a | ||||||||||||||||||||
| (2) |
Notes
B1: CAO for north-west corner method (six correct figures in correct cells only, no zeros)
B1: CAO for initial solution (2942)
| Scheme | Marks | AO | ||||||||||||||||||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| M1 A1 | 2.1 1.1b | ||||||||||||||||||||||||||||||||||||||||
| M1 | 1.1b | ||||||||||||||||||||||||||||||||||||||||
| Entering cell is AS and exiting cell is BS | A1 | 2.2a | ||||||||||||||||||||||||||||||||||||||||
| (4) | ||||||||||||||||||||||||||||||||||||||||||
| (9 marks) |
Notes
M1: Finding 7 shadow costs and 6 improvement indices
A1: CAO
M1: A valid route shown, their most negative II chosen, only one empty square used, \(\theta\)’s balance
A1: cao – (no zeros) including deducing entering and exiting cells
For reference:
| R | S | T | Supply | |
|---|---|---|---|---|
| A | 23 | 17 | 24 | 34 |
| B | 15 | 29 | 32 | 27 |
| C | 25 | 25 | 27 | 41 |
| D | 19 | 20 | 25 | 18 |
| Demand | 44 | 37 | \(k\) |