Higher November 2024 Paper 3 Q16

16 Rearrange \(\quad y = \displaystyle\sqrt{\left(\frac{x}{2} + 1\right)} \quad\) to make \(x\) the subject. [3 marks]

Mark scheme

Answer	Mark	Comments
\(y^2 = \dfrac{x}{2} + 1\)	M1
\(y^2 - 1 = \dfrac{x}{2}\) or \(1 - y^2 = -\dfrac{x}{2}\) or \(2y^2 = x + 2\) or \(2y^2 - 2\) or \(2(y^2 - 1)\)	M1dep
\(x = 2y^2 - 2\) or \(x = 2(y^2 - 1)\)	A1

\(x = 2y^2 - 2\) in working with \(2y^2 - 2\) on answer line

M1M1A1