Higher November 2018 Paper 3 Q17
17 \(w = \dfrac{3}{5\sqrt{x}}\)
Circle the expression for \(w^2\) [1 mark]
- \(\dfrac{6}{10x^2}\)
- \(\dfrac{9}{25x^2}\)
- \(\dfrac{6}{10x}\)
- \(\dfrac{9}{25x}\)
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{9}{25x}\) | B1 |
17 \(w = \dfrac{3}{5\sqrt{x}}\)
Circle the expression for \(w^2\) [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{9}{25x}\) | B1 |