Higher November 2018 Paper 3 Q17

AQACurrent spec1 markIndices

17 \(w = \dfrac{3}{5\sqrt{x}}\)

Circle the expression for \(w^2\) [1 mark]

  • \(\dfrac{6}{10x^2}\)
  • \(\dfrac{9}{25x^2}\)
  • \(\dfrac{6}{10x}\)
  • \(\dfrac{9}{25x}\)