Higher November 2017 Paper 2 Q11
11 Circle the expression that is equivalent to \(\quad \dfrac{3x^2}{6x^2 + 3}\) [1 mark]
- \(\dfrac{x^2}{2x^2 + 3}\)
- \(\dfrac{x^2}{6x^2 + 1}\)
- \(\dfrac{x^2}{2x^2 + 1}\)
- \(\dfrac{1}{2} + x^2\)
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{x^2}{2x^2 + 1}\) | B1 |