Foundation June 2017 Paper 2 Q28
28 Rearrange \(\qquad y = \dfrac{x}{3} + 9 \qquad\) to make \(x\) the subject. [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(y - 9 = \dfrac{x}{3}\) or \(3y = x + 27\) or \(3y - 27\) or \(3(y - 9)\) | M1 | A correct first step in rearranging or the correct rearrangement without \(x =\) |
| \(x = 3y - 27\) or \(x = 3(y - 9)\) | A1 | Accept \(\;3y - 27 = x\) or \(3(y - 9) = x\) |
Additional guidance
| Accept \(-27 + 3y\) for \(3y - 27\) throughout | |
| \(x = 3y - 27\) in working with answer \(\;3y - 27\) | M1A1 |
| \(x = (y - 9)3\) \(\quad\) (unless recovers) | M1A0 |
| \(x = y3 - 27\) \(\quad\) (unless recovers) | M1A0 |
| Multiplication signs are acceptable for M1 but not A1 | |
| \(x = 3 \times y - 27\) | M1A0 |
| \(3 \times y = x + 3 \times 9\) | M1 |