Intermediate June 2017 Unit 2 Q14
14. A right-angled triangle LMN is shown below.
LN = 16·9 cm and LM = 6·5 cm.

Diagram not drawn to scale
Calculate the length MN. [3]
| Scheme | Marks | Comments |
|---|---|---|
| 16·92 = 6·52 + MN2 or equivalent. | M1 | Allow M1 for 16·92 − 6·52. |
| (MN2) = 243·36 or (MN) =√243·36 | A1 | |
| (MN =) 15·6(cm) | A1 | C.A.O. |