Higher November 2018 Unit 1 Q13
13. Rearrange the following formula to make \(c\) the subject. [4]
\[\frac{6c - 3d}{c + 2} = g\]| Scheme | Marks | Comments |
|---|---|---|
| \(6c - 3d = g(c + 2)\) | B1 | FT until 2nd error, provided equivalent difficulty. May be implied by further working. |
| \(6c - gc = 3d + 2g\) | B1 | Includes correct expansion and rearrangement. |
| \(c(6 - g) = 3d + 2g\) | B1 | |
| \(c = (3d + 2g)/(6 - g)\) or equivalent | B1 | Mark final answer. |