Higher November 2020 Unit 1 Q12
12. Express the following as a single fraction in its simplest form. [3]
\[\frac{6}{3x-5} - \frac{4}{2x+1}\]| Scheme | Marks | Comments |
|---|---|---|
| \(6\,(2x + 1) - 4\,(3x - 5)\) as a numerator within a single fraction | M1 | Allow intention of brackets, e.g. \(6 \times 2x + 1 - 4 \times 3x - 5\) |
| \((3x - 5)\,(2x + 1)\) as a denominator | M1 | |
| \(26 / (3x - 5)\,(2x + 1)\) | A1 | CAO. Allow \(26 / (6x^2 - 7x - 5)\) (If expanded, the denominator must be correct.) If M1 M1 A1, penalise further incorrect work –1. If no marks awarded, then SC1 for sight of 26. |