Higher June 2017 Paper 1 Q7
7. Make \(y\) the subject of this formula. [3]
\[9x = p(8 + y) + 5\]| Scheme | Marks | Comments |
|---|---|---|
| \(9x - 5 = p(8 + y)\) or \(9x = 8p + py + 5\) | B1 | FT until 2nd error |
| \(\dfrac{9x - 5}{p} = 8 + y\) or \(9x - 5 - 8p = py\) | B1 | FT |
| \(y = \dfrac{9x - 5}{p} - 8\) or \(y = \dfrac{9x - 5 - 8p}{p}\) | B1 | FT Implies previous B2. Mark final answer. |
| (3) |