Higher June 2022 Paper 1 Q14
14. Rearrange this formula to make \(a\) the subject. [4]
\[\dfrac{a^3b}{7} + 5 = c\]| Scheme | Marks | Comments |
|---|---|---|
| FT until second error; marks may be awarded in a different order | ||
| \(a^3b + 35 = 7c\) or \(\dfrac{a^3b}{7} = c - 5\) | B1 | |
| \(a^3b = 7c - 35\) or \(a^3b = 7(c - 5)\) | B1 | |
| \(a^3 = \dfrac{7c - 35}{b}\) or \(a^3 = \dfrac{7(c - 5)}{b}\) | B1 | |
| \(a = \sqrt[3]{\dfrac{7c - 35}{b}}\) or \(a = \sqrt[3]{\dfrac{7(c - 5)}{b}}\) | B1 | Mark final answer |
| (4) |