4400 Higher June 2006 Paper 3 Q2
2 Solve \(7 - 4x = 10\)
(3)
| Scheme | Marks |
|---|---|
| \(7 = 4x + 10\) or \(-4x = 10 - 7\) | M1 |
| \(4x = -3\) or \(-4x = 3\) | M1 |
| \(-\frac{3}{4}\) or −0.75 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: may be implied by second M1
A1: Condone \(\frac{3}{-4}\)