4400 Higher June 2004 Paper 4 Q11
11 Solve \(4(x - 3) = 7x - 10\)
(3)
| Scheme | Marks |
|---|---|
| \(4x - 12 = 7x - 10\) | B1 |
| \(-12 + 10 = 7x - 4x\) or \(-2 = 3x\) | M1 |
| \(-\frac{2}{3}\) oe | A1 |
| (3) | |
| (3 marks) |
Notes
B1: for \(4x - 12\) seen
‹ Previous212 of 212 in Solving Simple Equations