4MA0 Foundation June 2011 Paper 1 Q20
20 The perimeter of a triangle is 90 cm.
The lengths of the sides of the triangle are in the ratios 3 : 5 : 7
Work out the length of the longest side of the triangle.
(3)
| Scheme | Marks |
|---|---|
| 3 + 5 + 7 or 15 | M1 |
| 90 ÷ (3 + 5 + 7) or 90 ÷ 15 or 6 or \(\dfrac{7}{15}\) oe | M1 |
| 42 | A1 |
| (3) | |
| (Total 3 marks) |
Notes
M1: 15 may be denominator of fraction or coefficient in an equation such as \(15x = 90\)
M1: dep
A1: Also award for 18 : 30 : 42