4MA0 Higher June 2015 Paper 3R Q15
15 Use algebra to show that the recurring decimal \(0.\dot{4}1\dot{7} = \dfrac{139}{333}\)
(2)
| Scheme | Marks |
|---|---|
| \(x = 0.417417\ldots\) \(1000x = 417.417\ldots\) \(999x = 417\) | M1 |
| show | A1 |
| (2) |
Notes
M1: M1 for \(1000x = 417.417\ldots\) and \(x = 0.417417\ldots\)
accept \(x = 0.\dot{4}1\dot{7}\) selected for use oe
A1: for \(\dfrac{417}{999}\) cso