4MA0 Higher June 2015 Paper 3R Q1
1 The table shows information about the numbers of fish caught by 40 people in one day.
| Number of fish | Frequency |
|---|---|
| 0 | 2 |
| 1 | 12 |
| 2 | 15 |
| 3 | 8 |
| 5 | 2 |
| 8 | 1 |
(a) Work out the mean number of fish caught. (3)
(b) Work out what percentage of the 40 people caught less than 2 fish. (2)
| Scheme | Marks |
|---|---|
| [2 × 0] + 12 × 1 + 15 × 2 + 8 × 3 + 2 × 5 + 1 × 8 (= 84) or [0] + 12 + 30 + 24 + 10 + 8 | M1 |
| “84” ÷ 40 | M1 dep |
| 2.1 | A1 |
| (3) |
Notes
M1: (2 × 0) may be omitted;
allow one error
M1 dep: NB: Products do not have to be evaluated
| Scheme | Marks |
|---|---|
| \(\dfrac{14}{40} \times 100\) oe | M1 |
| 35 | A1 |
| (2) |
Notes
M1: allow \(\dfrac{26}{40} \times 100\) or \(\dfrac{29}{40} \times 100\)