4MA0 Higher June 2012 Paper 4 Q5
5
(a) Show that \(\dfrac{4}{5} \div \dfrac{7}{15} = 1\dfrac{5}{7}\) (2)
(b) Show that \(5\dfrac{1}{4} - 1\dfrac{2}{3} = 3\dfrac{7}{12}\) (3)
| Scheme | Marks |
|---|---|
| \(\frac{4}{5} \times \frac{15}{7}\) | M1 |
| \(\frac{12}{7}\) oe | A1 |
| (2) |
Notes
M1: or \(\frac{12a}{15a} \div \frac{7a}{15a}\) (denominators the same and a multiple of 15)
A1: dep on M1. Improper fraction equivalent to \(1\frac{5}{7}\) required produced directly from M1
| Scheme | Marks |
|---|---|
| \(\frac{21}{4} - \frac{5}{3}\) | M1 |
| \(\frac{63a}{12a} - \frac{20a}{12a}\) | M1 |
| \(\frac{43}{12}\) oe | A1 |
| (3) | |
| (Total 5 marks) |
Notes
M1: Correct improper fractions
M1: Correct fractions with a common denominator a multiple of 12
A1: dep on M2 Improper fraction required.
Alt method
| Scheme | Marks |
|---|---|
| (5) \(\frac{3}{12}\) − (1) \(\frac{8}{12}\) (i.e. can ignore integer parts) | M1 |
| − \(\frac{5}{12}\) | M1 |
| A1 |
Notes
A1: Improper fraction required or 4 − \(\frac{5}{12}\). Ans dep on M2.
Alt method
| Scheme | Marks |
|---|---|
| (4) \(\frac{5}{4}\) − (1) \(\frac{2}{3}\) (i.e. can ignore integer parts) | M1 |
| (4) \(\frac{15}{12}\) − (1) \(\frac{8}{12}\) (i.e. can ignore integer parts) | M1 |
| (3 +) \(\frac{7}{12}\) or improper fraction | A1 |
Notes
A1: Ans dep on M2
NB: Follow one strand that gives most marks.