4MA0 Foundation January 2016 Paper 2R Q21
21 Show that \(\dfrac{3}{4} + \dfrac{4}{5} = 1\dfrac{11}{20}\)
(2)
| Scheme | Marks |
|---|---|
| \(\dfrac{3 \times 5}{20} + \dfrac{4 \times 4}{20}\) or \(\dfrac{15}{20} + \dfrac{16}{20}\) | M1 |
| \(\dfrac{31}{20}\) | A1 |
| (2) | |
| Total 2 marks |
Notes
M1: for any pair of correct fractions with denominator a multiple of 20
A1: dependent on M1
Alternative
| Scheme | Marks |
|---|---|
| 0.75 + 0.8 = 1.55 | M1 |
| \(1\dfrac{55}{100}\) | A1 |
Notes
A1: dependent on M1