1MA0 Higher November 2015 Paper 2 Q11
11
(a) Solve \(3x^2 = 147\) (2)
(b) Work out the value of \(2^{-3}\) (1)
(c) Simplify \((3x^2)^3\) (2)
\(w = 4p - 16\)
(d) Make \(p\) the subject of this formula. (2)
| Answer | Mark | Notes |
|---|---|---|
| \(\pm 7\) | 2 | M1 for intent to divide both sides by 3 as a first step or answer of 7 or \(-7\) A1 \(\pm 7\) |
| Answer | Mark | Notes |
|---|---|---|
| 0.125 or \(\tfrac{1}{8}\) | 1 | B1 cao |
| Answer | Mark | Notes |
|---|---|---|
| \(27x^6\) | 2 | M1 for either 27 or \(x^6\) in a two term product A1 cao |
| Answer | Mark | Notes |
|---|---|---|
| \(p = \dfrac{w + 16}{4}\) | 2 | M1 for \(\div 4\) throughout or adding 16 to both sides as a first step A1 \(p = \dfrac{w + 16}{4}\) oe |