4MA0 Foundation June 2016 Paper 2R Q16
16 Show that \(\dfrac{3}{8} + \dfrac{5}{24} = \dfrac{7}{12}\)
(2)
| Scheme | Marks |
|---|---|
| eg \(\dfrac{9}{24} + \dfrac{5}{24} = \dfrac{14}{24}\) | M1 |
| Shown | A1 |
| (2) |
Notes
M1: for conversion to two correct fractions with the same denominator
A1: for a correct fraction equivalent to \(\dfrac{7}{12}\)