4MA0 Higher January 2018 Paper 3 Q12
12 Solve \(\dfrac{x + 4}{3} + \dfrac{2x + 3}{4} = 7\)
Show clear algebraic working.
(3)
| Scheme | Marks |
|---|---|
e.g. \(\dfrac{4(x + 4)}{12} + \dfrac{3(2x + 3)}{12}\;(= 7)\) OR \(\dfrac{4(x + 4) + 3(2x + 3)}{12}\;(= 7)\) OR \(4(x + 4) + 3(2x + 3) = 7 \times 3 \times 4\) | M1 |
| e.g. \(4x + 16 + 6x + 9 = 7 \times 12\) OR \(10x + 25 = 7 \times 12\) | M1 |
| 5.9 oe | A1 |
| (3) |
Notes
M1: for dealing with fractions
e.g. express LHS as the sum of 2 fractions with denominator of 12 or a multiple of 12 (if brackets expanded, condone 1 error)
or
express LHS as a single fraction with denominator of 12 or a multiple of 12 (if brackets expanded, condone 1 error) or multiplying both sides by 12 or a multiple of 12 (if brackets expanded, condone 1 error))
M1: for dealing with fraction(s) and expanding brackets (condone 1 error in expansion of brackets)
A1: dep on M1 gained