FP2 June 2014 Q4

EdexcelOld spec10 marksDe Moivre's Theorem

4.

(a) Use de Moivre’s theorem to show that \[\cos 6\theta = 32\cos^6\theta - 48\cos^4\theta + 18\cos^2\theta - 1\] (5)
(b) Hence solve for \(0 \leqslant \theta \leqslant \dfrac{\pi}{2}\) \[64\cos^6\theta - 96\cos^4\theta + 36\cos^2\theta - 3 = 0\] giving your answers as exact multiples of \(\pi\). (5)