M4 June 2012 Q5
5.

A uniform rod \(AB\), of length \(4a\) and weight \(W\), is free to rotate in a vertical plane about a fixed smooth horizontal axis which passes through the point \(C\) of the rod, where \(AC = 3a\). One end of a light inextensible string of length \(L\), where \(L \gt 10a\), is attached to the end \(A\) of the rod and passes over a small smooth fixed peg at \(P\) and another small smooth fixed peg at \(Q\). The point \(Q\) lies in the same vertical plane as \(P\), \(A\) and \(B\). The point \(P\) is at a distance \(3a\) vertically above \(C\) and \(PQ\) is horizontal with \(PQ = 4a\). A particle of weight \(\dfrac{1}{2}W\) is attached to the other end of the string and hangs vertically below \(Q\). The rod is inclined at an angle \(2\theta\) to the vertical, where \(-\pi \lt 2\theta \lt \pi\), as shown in Figure 1.
| Scheme | Marks |
|---|---|
| \(V = -Wa\cos 2\theta + \dfrac{1}{2}W\left\{3a - (L - 6a\cos\theta - 4a)\right\}\) | B1 M1 A1 |
| \(= -Wa\cos 2\theta + 3Wa\cos\theta + \left(\dfrac{7Wa}{2} - \dfrac{WL}{2}\right)\) | |
| \(= Wa(3\cos\theta - \cos 2\theta) + \text{constant}\ *\) | A1 |
| (4) |
Notes
B1 GPE of rod e.g. \(-Wa\cos 2\theta\)
M1 GPE of the particle e.g. \(\dfrac{1}{2}W\left\{3a - (L - 6a\cos\theta - 4a)\right\}\). Condone 3a term missing.
A1 Correct expression including the 3a (unless in the GPE for the rod). Accept aef e.g. \(\sqrt{18a^2(1 + \cos 2\theta)}\) for \(6a\cos\theta\)
A1 Obtain the given answer correctly
| Scheme | Marks |
|---|---|
| \(\dfrac{\mathrm{d}V}{\mathrm{d}\theta} = Wa(-3\sin\theta + 2\sin 2\theta)\) | M1 A1 |
| For equilibrium, \(Wa(-3\sin\theta + 2\sin 2\theta) = 0\) | |
| \(\sin\theta(4\cos\theta - 3) = 0\) | DM1 A1 |
| \(\Rightarrow \theta = 0\) or \(\theta = \cos^{-1}\left(\dfrac{3}{4}\right)\) | A1 |
| \(\dfrac{\mathrm{d}^2V}{\mathrm{d}\theta^2} = Wa(-3\cos\theta + 4\cos 2\theta)\) | M1 |
| \(\theta = 0: \dfrac{\mathrm{d}^2V}{\mathrm{d}\theta^2} = Wa \gt 0 \Rightarrow\) stable | A1 |
| \(\theta = \cos^{-1}\tfrac{3}{4}: \dfrac{\mathrm{d}^2V}{\mathrm{d}\theta^2} = -\dfrac{7Wa}{4} \lt 0 \Rightarrow\) unstable | A1 |
| (8) | |
| (12 marks) |
Notes
M1 Differentiate the given \(V\) wrt \(\theta\)
A1 correct
DM1 Set their derivative = 0
A1 First answer
A1 Second answer - ignore \(\theta = -\cos^{-1}\left(\dfrac{3}{4}\right)\). 0.72 rads or better
M1 Obtain the second derivative of \(V\) and substitute one of their values for \(\theta\)
A1 Correct working and conclusion for one value
A1 Correct working and reasoning for the second. ISW for work on \(-\cos^{-1}\left(\dfrac{3}{4}\right)\)