S2 June 2013 Q7
7. A telesales operator is selling a magazine. Each day he chooses a number of people to telephone. The probability that each person he telephones buys the magazine is 0.1
A call centre also sells the magazine. The probability that a telephone call made by the call centre sells a magazine is 0.05
The call centre telephones 100 people every hour.
| Scheme | Marks |
|---|---|
| Distribution \(X \sim \mathrm{B}(n, 0.1)\) | B1 |
| (1) |
Notes
B1 for “binomial” or B(…
| Scheme | Marks |
|---|---|
| \(Y \sim \mathrm{B}(10, 0.1)\) | B1 |
| \(\mathrm{P}(Y \geqslant 4) = 1 - \mathrm{P}(Y \leqslant 3)\) | M1 |
| \(= 1 - 0.9872\) | |
| \(= 0.0128\) | A1 |
| (3) |
Notes
B1 writing or using B(10,0.1)
M1 writing or using \(1 - \mathrm{P}(Y \leqslant 3)\)
A1 awrt 0.0128
| Scheme | Marks |
|---|---|
| \(0.9^n \lt 0.05\) or \(1 - (0.9)^n \gt 0.95\) | M1 |
| \(n \gt 28.4\) | A1 |
| \(n = 29\) | A1 |
| (3) |
Notes
Alternative
| Scheme | Marks |
|---|---|
| B(28,0.1): P(0) = 0.0523 | M1 |
| B(29,0.1): P(0) = 0.0471 | A1 |
| \(n = 29\) | A1cao |
| (3) |
M1 \((0.9)^n \lt 0.05\),oe, or \((0.9)^n = 0.05\),oe, or \((0.9)^n \gt 0.05\), oe, or seeing 0.0523 or seeing 0.0471
1st A1 [P(0)] = 0.0471 or getting awrt 28.4 May be implied by correct answer.
2nd A1 cao \(n = 29\) should not come from incorrect working.
NB An answer of 29 on its own with no working gains M1A1A1
| Scheme | Marks |
|---|---|
| \(C \sim \mathrm{Po}(5)\) | B1 |
| \(\mathrm{P}(C \gt 10) = 1 - \mathrm{P}(C \leqslant 10)\) | M1 |
| \(= 1 - 0.9863\) | |
| \(= 0.0137\) | A1 |
| (3) | |
| (10 marks) |
Notes
B1 writing or using Po(5)
M1 writing or using \(1 - \mathrm{P}(C \leqslant 10)\)
A1 awrt 0.0137