S2 January 2010 Q1
1. A manufacturer supplies DVD players to retailers in batches of 20. It has 5% of the players returned because they are faulty.
Find the probability that a batch contains
| Scheme | Marks |
|---|---|
| \(X \sim B(20, 0.05)\) | B1 B1 |
| (2) |
Notes
1st B1 for binomial
2nd B1 for 20 and 0.05 o.e
These must be in part (a)
| Scheme | Marks |
|---|---|
| \(\mathrm{P}(X = 0) = 0.95^{20} = 0.3584859\ldots\) or 0.3585 using tables. | M1 A1 |
| (2) |
Notes
M1 for finding \((p)^{20}\) \(0 \lt p \lt 1\) this working needs to be seen if answer incorrect to gain the M1
A1 awrt 0.358 or 0.359.
NB In parts b, c and d correct answers with no working gain full marks
| Scheme | Marks |
|---|---|
| \(\mathrm{P}(X \gt 4) = 1 - \mathrm{P}(X \leqslant 4)\) | M1 |
| \(= 1 - 0.9974\) \(= 0.0026\) | A1 |
| (2) |
Notes
M1 for writing \(1 - \mathrm{P}(X \leqslant 4)\)
or \(1 - [\,\mathrm{P}(X = 0) + \mathrm{P}(X = 1) + \mathrm{P}(X = 2) + \mathrm{P}(X = 3) + \mathrm{P}(X = 4)]\)
or \(1 - 0.9974\)
or \(1 - 0.9568\)
A1 awrt 0.0026 or \(2.6 \times 10^{-3}\), do not accept a fraction e.g. 26/10000
NB In parts b, c and d correct answers with no working gain full marks
| Scheme | Marks |
|---|---|
| \(\text{Mean} = 20 \times 0.05 = 1\) | B1 |
| \(\text{Variance} = 20 \times 0.05 \times 0.95 = 0.95\) | B1 |
| (2) | |
| (8 marks) |
Notes
1st B1 for 1
2nd B1 for 0.95
NB In parts b, c and d correct answers with no working gain full marks