Higher November 2022 Paper 5 Q9
9 A student says that they have placed the following values in order starting with the smallest.
\[\left(\frac{1}{10}\right)^2 \qquad \sqrt{0.25} \qquad 4^{-1}\]Has the student done this correctly?
Show how you decide. [4]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| [\(\left(\frac{1}{10}\right)^2\) =] \(\frac{1}{100}\) or 0.01 [\(\sqrt{0.25}\) =] 0.5 or \(\frac{1}{2}\) [\(4^{-1}\)] = \(\frac{1}{4}\) or 0.25 | M3 | M1 for each | For all method marks accept oe %’s If e.g. [\(\left(\frac{1}{10}\right)^2\) =] \(\frac{1}{100}\) = 0.1 then M0 Accept – 0.5 or ±0.5 oe for \(\sqrt{0.25}\) or \(\frac{5}{10}\) |
| No oe and \(\left(\frac{1}{10}\right)^2\), \(4^{-1}\), \(\sqrt{0.25}\) oe | A1 | Accept equivalents Accept No oe and \(4^{-1}\) and \(\sqrt{0.25}\) need to swap places oe If – 0.5 oe for \(\sqrt{0.25}\), then accept order is \(\sqrt{0.25}\), \(\left(\frac{1}{10}\right)^2\), \(4^{-1}\) oe | |