Foundation June 2019 Paper 2 Q6
6 Here is a function machine.
(a)
(i) Find the output when the input is 7. [1]
(ii) Find the input when the output is 42. [2]
(b) The input is \(x\) and the output is \(y\).
Write an equation for \(y\) in terms of \(x\). [2]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| (i) 32 | 1 | ||
| (ii) 9 | 2 | M1 for either step reversed soi | eg +3, \(\div\) 5, 45 |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(y = 5x - 3\) final answer | 2 | M1 for \(5x - 3\) seen or \(y = 5x + 3\) in final answer or \(y = kx - 3\) (\(k \ne 0\)) in final answer or \(y = 5x - c\) where \(c \gt 0\) If 0 scored SC1 for \(x = \dfrac{y + 3}{5}\) final answer | Accept \(5x - 3 = y\) Allow \(x \times 5 - 3\) for 1 or 2 marks Accept \(5x + 3 = y\) or \(kx - 3 = y\) or \(5x - c = y\) |