Higher November 2017 Paper 5 Q17
17 Solve the inequality.
\(x^2 - 5x - 6 \leqslant 0\) [4]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(-1 \leqslant x \leqslant 6\) oe | 4 | M2 for \((x - 6)(x + 1)\) [\(\leqslant\) 0 ] oe | For M2 or M1, condone [= 0] M2 for correct formula or complete square condone 1 error M1 for \((x - 2.5)^2\) oe seen or for correct formula with 2 errors |
| Or M1 for \((x + a)(x + b)\) [\(\leqslant\) 0 ] where \(ab = -6\) or \(a + b = -5\) | |||
| B1 for –1 and 6 soi | Could be seen as roots on sketch of graph or in wrong inequality | ||