Higher June 2019 Paper 2R Q2

EdexcelHigherCurrent spec3 marksFractions

2 Show that \(5\dfrac{2}{3} - 2\dfrac{3}{4} = 2\dfrac{11}{12}\)

(3)

Mark scheme

Scheme	Marks
\(\dfrac{17}{3}\,(-)\,\dfrac{11}{4}\) or \(5\dfrac{8}{12}\,(-)\,2\dfrac{9}{12}\)	M1
\(\dfrac{68}{12} - \dfrac{33}{12}\) or \(4\dfrac{20}{12} - 2\dfrac{9}{12}\)	M1
Working required \(\dfrac{35}{12} = 2\dfrac{11}{12}\)	A1
	(3)
	(3 marks)

M1: Sight of \(\dfrac{17}{3}\) and \(\dfrac{11}{4}\) or \(5\dfrac{8}{12}\) and \(2\dfrac{9}{12}\)

M1: or \(\dfrac{68n}{12n} - \dfrac{33n}{12n}\)

A1: Dep on M2

Mark scheme (ALT 1)

Scheme	Marks
\(3\,(+)\left(\dfrac{2}{3} - \dfrac{3}{4}\right)\)	M1
\(3\,(+)\left(\dfrac{8}{12} - \dfrac{9}{12}\right)\)	M1
Working required \(3 - \dfrac{1}{12} = 2\dfrac{11}{12}\)	A1

A1: Dep on M2

Mark scheme (ALT 2)

Scheme	Marks
\(4\dfrac{5}{3}\,(-)\,2\dfrac{3}{4}\) \(2\,(+)\left(\dfrac{5}{3} - \dfrac{3}{4}\right)\)	M1
\(2\,(+)\left(\dfrac{20}{12} - \dfrac{9}{12}\right)\)	M1
Working required \(= 2\dfrac{11}{12}\)	A1

A1: Dep on M2