Higher June 2019 Paper 1R Q11
11 3 years ago, the ratio of Tom’s age to Clemmie’s age was 2 : 7
Tom is now 15 years old and Clemmie is now \(x\) years old.
Find the value of \(x\).
(3)
| Scheme | Marks |
|---|---|
\(15 - 3 : x - 3 = 2 : 7\) or (15 – 3) ÷ 2 (= 6) or (\(n\) =) \((15 - 3) \div \dfrac{2}{2 + 7}\) (= 54) where \(n\) is the total age 3 years ago | M1 |
\(\dfrac{x - 3}{15 - 3} = \dfrac{7}{2}\) oe or 7 × “6” (= 42) or \(\text{``}{54}\text{''} \times \dfrac{7}{2 + 7}\) (= 42) | M1 |
| 45 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: M2 for \(\dfrac{(15 - 3) \times 7}{2}\) (= 42)