Higher June 2022 Paper 1R Q6
6 Show that \(2\dfrac{2}{3} + 3\dfrac{3}{4} = 6\dfrac{5}{12}\)
(3)
| Scheme | Marks |
|---|---|
| \(\dfrac{8}{3}(+)\dfrac{15}{4}\) or \((2)\dfrac{8}{12}(+)(3)\dfrac{9}{12}\) or \((2)\dfrac{8a}{12a}(+)(3)\dfrac{9a}{12a}\) | M1 |
eg \(\dfrac{8 \times 4 + 15 \times 3}{3 \times 4}\) or \(\dfrac{32}{12} + \dfrac{45}{12}\) or \(\dfrac{32a}{12a} + \dfrac{45a}{12a}\) or \(2\dfrac{8}{12} + 3\dfrac{9}{12} = 5\dfrac{17}{12}\) oe | M1 |
\(\dfrac{32}{12} + \dfrac{45}{12} = \dfrac{77}{12} = 6\dfrac{5}{12}\) or \(5\dfrac{17}{12} = 6\dfrac{5}{12}\) or if shows \(6\dfrac{5}{12} = \dfrac{77}{12}\) at the beginning then show that the addition comes to \(\dfrac{77}{12}\) Answer: Shown | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for correct improper fractions or fractional part of numbers written correctly over a common denominator
M1: for correct fractions with a common denominator of 12 or a multiple of 12
A1: dep on M2 for a correct answer from fully correct working or shows that RHS = \(\dfrac{77}{12}\) and fully correct working shows LHS = \(\dfrac{77}{12}\)