Foundation June 2019 Paper 2R Q13
13
(a) Solve \(\;3f - 5 = 11\) (2)
(b) Expand \(\;w(w + 3)\) (1)
\(y = 5e^2 + 20\)
(c) Work out the value of \(y\) when \(e = -3\) (2)
(d) Factorise \(\;x^2 - 5x - 36\) (2)
| Scheme | Marks |
|---|---|
| \(3f = 11 + 5\) or \(3f = 16\) | M1 |
| \(\dfrac{16}{3}\) oe | A1 |
| (2) |
Notes
M1: A correct rearrangement of numbers on one side
A1: accept \(5\dfrac{1}{3}\) or 5.3 with recurring symbol or 5.33 (at least 2 3’s)
NB. 16/3 in body of script then 5.3 on ans line = M1 A1
5.3 on ans line with no working = M1 A0
| Scheme | Marks |
|---|---|
| \(w^2 + 3w\) | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| \(5(-3)^2 + 20\) | M1 |
| 65 | A1 |
| (2) |
Notes
A1: Ans of – 25 = M1 A0 if substitution seen
| Scheme | Marks |
|---|---|
| M1 | |
| \((x + 4)(x - 9)\) | A1 |
| (2) | |
| (7 marks) |
Notes
M1: For \((x + a)(x + b)\) where \(ab = -36\) and \(a\) and \(b\) are integers
A1: Ignore extension to roots \(x = -4\) & 9