Foundation January 2022 Paper 2 Q7
7 \(\dfrac{3}{8}\) of the members of a squash club are children.
\(\dfrac{5}{6}\) of these children are right-handed.
What fraction of the members of the squash club are right-handed children?
Give your answer as a fraction in its simplest form.
Show your working clearly.
(3)
| Scheme | Marks |
|---|---|
\(\dfrac{3}{8} \times \dfrac{5}{6}\) oe eg 0.375 ÷ 6 × 5 Allow 0.375 × 0.83…. oe or eg \(\dfrac{3}{8} \times 48 = 18\) and eg \(\dfrac{5}{6} \times 18 = 15\) | M1 |
eg \(\dfrac{3}{8} \times \dfrac{5}{6} = \dfrac{15}{48}\) or \(\dfrac{\cancel{3}^{\,1}}{8} \times \dfrac{5}{\cancel{6}_{\,2}}\) 0.375 × 0.83…. = 0.31….. or \(\dfrac{\text{“}15\text{”}}{\text{“}48\text{”}}\) | M1 |
Working required Answer: \(\dfrac{5}{16}\) | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for showing intention to multiply the two given fractions or using a number of members that is a multiple of 48 to work out the number of right-handed children.
M1: For an attempt to multiply fractions or
Dividing their 15 by their 48
A1: dep on M1