Foundation June 2022 Paper 2 Q5
5 Jian has two fair spinners.
Spinner A is 3-sided and can land on 1, 2 or 3
Spinner B is 5-sided and can land on 2, 4, 6, 8 or 10
Jian spins each spinner once.
He adds together the number that spinner A lands on and the number that spinner B lands on to get his total score.
(a) Complete the table to show all possible total scores.
Five of the total scores have been done for you. (2)
Five of the total scores have been done for you. (2)
| Spinner A | ||||
|---|---|---|---|---|
| 1 | 2 | 3 | ||
| Spinner B | 2 | 3 | ||
| 4 | 7 | |||
| 6 | 7 | |||
| 8 | 10 | |||
| 10 | 12 | |||
(b) Find the probability that
(i) Jian’s total score is an odd number (1)
(ii) Jian’s total score is less than 9 (1)
| Scheme | Marks | ||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| B2 | ||||||||||||||||||||||||
| (2) |
Notes
B2: For all 10 entries correct in table
(B1 for 6, 7, 8 or 9 correct entries)
| Scheme | Marks |
|---|---|
(i) Answer: \(\dfrac{10}{15}\) | B1ft |
(ii) Answer: \(\dfrac{8}{15}\) | B1ft |
| (2) | |
| (4 marks) |
Notes
B1ft: oe eg \(\dfrac{2}{3}\) or 0.66, 0.67, 0.666, 0.667 etc
B1ft: 0.53(333…)
(SC B1(marks in (ii)) if both parts using “correct values” but incorrect probability notation eg 10 : 15, 8 : 15)