Foundation June 2022 Paper 1 Q11
11 Johan wants to make some small cakes.
He finds a recipe that says he needs 360 grams of flour to make 15 small cakes.
Johan has 0.85 kg of flour.
Johan works out how much flour he would need to make 38 small cakes, using the information given in the recipe.
Does Johan have enough flour, according to the recipe, to make 38 small cakes?
Show your working clearly.
(4)
| Scheme | Marks |
|---|---|
| 0.85 × 1000 (= 850) or 360 ÷ 1000 (= 0.36) | M1 |
360 ÷ 15 (= 24) or “0.36” ÷ 15 (= 0.024) or “850” ÷ 38 (= 22.368….) or 0.85 ÷ 38 (= 0.022368….) or “850” ÷ 360 \(\left(= \dfrac{85}{36} = 2.3(6\ldots)\right)\) or \(\left(\dfrac{38}{15} =\right) 2\dfrac{8}{15}\) (= 2.5....) | M1 |
360 ÷ 15 (= 24) and “850” ÷ 38 (= 22.368….) or “0.36” ÷ 15 (= 0.024) and 0.85 ÷ 38 (= 0.022368….) or 360 ÷ 15 (= 24) and “850” ÷ 24 (= 35.4…) or “0.36” ÷ 15 (= 0.024) and 0.85 ÷ ‘0.024’ (= 35.4…) or “850” ÷ 360 \(\left(= \dfrac{85}{36} = 2.3(6\ldots)\right)\) and “2.3(6…)” × 15 (= 35.4) or \(\left(\dfrac{38}{15} =\right) 2\dfrac{8}{15}\) (= 2.5....) and \(\text{“}2\dfrac{8}{15}\text{”} \times \text{“}0.36\text{”}\) (= 0.912) or \(\left(\dfrac{38}{15} =\right) 2\dfrac{8}{15}\) (= 2.5....) and \(\text{“}2\dfrac{8}{15}\text{”} \times 360\) (= 912) or 360 ÷ 15 (= 24) and “24” × 38 (= 912) or “0.36” ÷ 15 (= 0.024) and “0.024” × 38 (= 0.912) | M1 |
| Working required Answer: No and correct figures seen | A1 |
| (4) | |
| (4 marks) |
Notes
M1: for a correct conversion of kg to g or g to kg
M1: oe
M1: calculations that compare the same amounts
e.g.
How much flour is needed for recipe and how much Johan has for each cake
or
Working out how many cakes Johann can make with his flour to compare with 38 cakes
or
Working out how much flour is needed to enable comparison with given figure of 0.85 kg
A1: No or statement that clearly states that there is not enough flour to make 38 cakes and correct figures - figures may be rounded in working and produce slightly different results which are acceptable eg “2.3(6…)” × 15 allow 34 – 36
Must compare 912 with 850 or implied by 62 seen
Alternative
| Scheme | Marks |
|---|---|
| 0.85 × 1000 (= 850) | M1 |
| E.g. 15 + 15 (= 30) or 15 ÷ 2 (= 7(.5) or 8) | M1 |
| E.g. 15 + 15 + 7(.5) (= 37(.5)) or 15 + 15 + 8 (= 38) | M1 |
| No and 37(.5) or 38 seen | A1 |
A1: oe No and 37(.5) or 38 seen
Alternative
| Scheme | Marks | ||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 0.85 × 1000 (= 850) | M1 | ||||||||||||||||||
| 360 ÷ 15 (= 24) | M1 | ||||||||||||||||||
E.g. for a build up method
| M1 | ||||||||||||||||||
| No and 36 seen | A1 |
A1: oe No and 36 seen