Foundation January 2023 Paper 1R Q19
19 Divya and Yuan each pay for a holiday at a special offer price.
| Divya’s holiday Normal price: $1600 Special offer: 16% off the normal price | Yuan’s holiday Normal price: $1400 Special offer: \(k\)% off the normal price |
The amount that Divya pays is the same as the amount that Yuan pays.
Work out the value of \(k\)
(4)
| Scheme | Marks |
|---|---|
| 1600 × 0.16 (= 256) oe or 1 – 0.16 (= 0.84) oe | M1 |
| 1600 – “256” or 1600 × “0.84” (= 1344) | M1 |
\(\dfrac{\text{“}1344\text{”}}{1400}\;(= 0.96)\) or \(\dfrac{1400 - \text{“}1344\text{”}}{1400}\;(= 0.04)\) or \(\dfrac{\text{“}1344\text{”}}{1400} \times 100\;(= 96)\) or \(\dfrac{1400 - \text{“}1344\text{”}}{1400} \times 100\) | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 4 | A1 |
| (4) | |
| (4 marks) |
Notes
A1: SCB1 for 1856 seen if no other marks awarded