Foundation January 2023 Paper 1 Q20
20 In a box, there are only green sweets, orange sweets and yellow sweets.
There are 280 sweets in the box so that
the number of green sweets : the number of orange sweets = 2 : 3
and
the number of orange sweets : the number of yellow sweets = 1 : 5
Work out how many green sweets there are in the box.
(3)
| Scheme | Marks |
|---|---|
| 2 : 3 : 15 oe or 20 or (1 : 5) × 3 or (1 : 5 =) 3 : 15 or \(2n : 3n : 15n\) e.g. 4 : 6 : 30 or G(reen) = 2, O(range) = 3 , Y(ellow) = 15 | M1 |
\(\dfrac{2}{\text{“}20\text{”}} \times 280\) oe or 14 × 2 or \(\dfrac{2}{\text{“}2\text{”} + \text{“}3\text{”} + \text{“}15\text{”}} \times 280\) oe or \(\dfrac{2n}{\text{“}2n\text{”} + \text{“}3n\text{”} + \text{“}15n\text{”}} \times 280\) oe | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 28 | A1 |
| (3) | |
| (3 marks) |
Notes
A1: or 28 : 42 : 210 or 28 , 42 , 210
If not in this order must be labelled correctly