Foundation June 2023 Paper 1R Q25
25 Kazi buys a car for 700 000 taka.
The value of the car depreciates by 12% each year.
Work out the value of the car at the end of 3 years.
Give your answer correct to the nearest taka.
(3)
| Scheme | Marks |
|---|---|
| 0.12 × 700 000 oe (= 84 000) or 0.88 × 700 000 oe (= 616 000) or 700 000 × \(0.88^2\) oe (= 542 080) | M1 |
| 0.88 × “616 000” oe (= 542 080) and 0.88 × “542 080” oe (= 477 030.4) | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 477 030 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for finding 12% or 88% of 700 000
M2 for 700 000 × \(0.88^3\) or 700 000 × \(0.88^4\) (= 419 786.75)
M1: for completing method to find the value of the car
A1: accept 477 030 – 477 031
SC: if no other marks gained award M1 for 0.36 × 700 000 oe or 252 000 or 0.64 × 700 000 oe or 448 000
accept (1 – 0.12) as equivalent to 0.88 throughout