Foundation June 2023 Paper 1R Q24
24
(a) Write \(5.6 \times 10^{-3}\) as an ordinary number. (1)
(b) Work out \(\dfrac{6 \times 10^3}{2.1 \times 10^{-4} + 9 \times 10^{-5}}\)
Give your answer in standard form. (2)
Give your answer in standard form. (2)
| Scheme | Marks |
|---|---|
| 0.0056 | B1 |
| (1) |
| Scheme | Marks |
|---|---|
20 000 000 oe eg \(20 \times 10^6\) or \(0.2 \times 10^8\) or \(2 \times 10^n\;\; n \neq 7\) or \(\dfrac{6 \times 10^{(3+5)}}{21 + 9}\) or \(\dfrac{6 \times 10^8}{30}\) or \(\dfrac{6 \times 10^3}{3 \times 10^{-4}}\) or \(\dfrac{6000}{0.0003}\) or \(\dfrac{6000}{3 \times 10^{-4}}\) | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: \(2 \times 10^7\) | A1 |
| (2) | |
| (3 marks) |