Foundation January 2020 Paper 1 Q6
6
(a) Write \(\dfrac{1}{4}\) as a decimal. (1)
(b) Write \(\dfrac{34}{10}\) as a mixed number in its simplest form. (2)
(c) Show that \(\dfrac{3}{4} \div \dfrac{15}{16} = \dfrac{4}{5}\) (2)
| Scheme | Marks |
|---|---|
| 0.25 | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| \(3\dfrac{4}{10}\) or \(\dfrac{17}{5}\) | M1 |
| \(3\dfrac{2}{5}\) | A1 |
| (2) |
Notes
M1: for converting to a simplified improper fraction or an unsimplified mixed fraction
| Scheme | Marks |
|---|---|
| \(\dfrac{3}{4} \times \dfrac{16}{15}\) or E.g. \(\dfrac{12}{16} \div \dfrac{15}{16}\) | M1 |
E.g. \(\dfrac{3}{4} \times \dfrac{16}{15} = \dfrac{48}{60} = \dfrac{4}{5}\) or \(\dfrac{12}{16} \div \dfrac{15}{16} = \dfrac{12}{15} = \dfrac{4}{5}\) Answer: Shown | A1 |
| (2) | |
| (5 marks) |
Notes
A1: for fully correct method leading to \(\dfrac{4}{5}\) – this must be preceded by a correct equivalent fraction e.g. \(\dfrac{48}{60}\), \(\dfrac{12}{15}\), \(\dfrac{16}{20}\) or fully correct cancelling must be seen within a multiplication