Foundation June 2021 Paper 2 Q15
15 Write 600 as a product of powers of its prime factors.
Show your working clearly.
(3)
| Scheme | Marks |
|---|---|
| eg 2 × 2 × 150 or 2² × 150 3 × 5 × 40 or 2 × 3 × 100 or 5 × 5 × 24 or 5² × 24  | M1 |
eg 2 × 2 × 2 × 3 × 5 × 5 | M1 |
| Working required. NB: answer must be given as a product of powers of prime factors Answer: \(2^3 \times 3 \times 5^2\) | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for at least 2 correct stages in prime factorisation which give 2 prime factors – may be in a factor tree or a table or listed eg 2, 2, 150 (see LHS for examples of the amount of work needed for the award of this mark, allow no more than one mistake ft (eg one mistake with 2 prime factors ft: 600 = 200 × 30 = 2 × 100 × 5 × 6)
M1: for 2, 2, 2, 3, 5, 5 (ignore 1s) (may be a fully correct factor tree or ladder)
A1: dep on M2
can be any order (allow \(2^3 \cdot 3 \cdot 5^2\))