Higher June 2019 Paper 2 Q15
15 Make \(m\) the subject of the formula \(f = \dfrac{3m + 4}{m - 1}\) (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(m = \dfrac{f + 4}{f - 3}\) | M1 | for multiplying both sides by \(m - 1\) eg \(f(m - 1) = 3m + 4\) (condone missing brackets for this mark only) |
| M1 | (dep) for a method to rearrange the formula to isolate terms in \(m\) in a correct equation eg \(fm - 3m = f + 4\) or \(-fm + 3m = -f - 4\) | |
| A1 | for \(m = \dfrac{f + 4}{f - 3}\) oe eg \(m = \dfrac{-f - 4}{-f + 3}\) |