Higher November 2018 Paper 1 Q1
1 Work out the value of \(\dfrac{3^7 \times 3^{-2}}{3^3}\) (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| 9 | M1 | for a correct first step, using the laws of indices to simplify eg. \(3^2\) or \(3^{7 + -2}\) or \(3^{7-3}\) or \(3^{-2-3}\) OR for using exact values, eg. \(2187 \times \dfrac{1}{9}\ (= 243)\) or \(2187 \div 27\ (= 81)\) or \(\dfrac{1}{27 \times 9}\ \left(= \dfrac{1}{243}\right)\) |
| A1 | cao |