Higher November 2023 Paper 1 Q17
17
(a) Factorise \(6x^2 - 5x - 4\) (2)
(b) Hence, or otherwise, solve \(6x^2 - 5x - 4 \lt 0\) (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| \((2x + 1)(3x - 4)\) | M1 | for \((2x \pm 1)(3x \pm 4)\) oe or for brackets which when expanded give 2 out of 3 terms correct |
| A1 | cao |
| Answer | Mark | Mark scheme |
|---|---|---|
| \(-\dfrac{1}{2} \lt x \lt \dfrac{4}{3}\) | M1 | for two critical values with at least one correct, \(-\dfrac{1}{2}\) or \(\dfrac{4}{3}\) or ft their critical values from (a) |
| A1 | for \(-\dfrac{1}{2} \lt x \lt \dfrac{4}{3}\) oe eg \(x \lt \dfrac{4}{3}, x \gt -\dfrac{1}{2}\) |