Foundation November 2021 Paper 2 Q25
25 Rearrange \(\quad g = 3h - 1 \quad\) to make \(h\) the subject. [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(3h = g + 1\) or \(g + 1 = 3h\) or \(h - \dfrac{1}{3} = \dfrac{g}{3}\) or \(\dfrac{g}{3} = h - \dfrac{1}{3}\) or \(\dfrac{g + 1}{3}\) or \(\dfrac{g}{3} + \dfrac{1}{3}\) | M1 | allow negative equivalents eg \(-3h = -g - 1\) correct rearrangement omitting \(h =\) |
| \(h = \dfrac{g + 1}{3}\) or \(h = \dfrac{g}{3} + \dfrac{1}{3}\) | A1 | oe fully simplified SC1 \(h = \dfrac{g - 1}{3}\) or \(h = \dfrac{g}{3} - \dfrac{1}{3}\) oe |
Additional guidance
| \(\dfrac{g + 1}{3} = h\) or \(\dfrac{g}{3} + \dfrac{1}{3} = h\) | M1A1 |
| Not fully simplified correct rearrangement eg \(h = \dfrac{-g - 1}{-3}\) | M1A0 |
| Correct solution followed by further incorrect simplification | M1A0 |