Higher June 2019 Paper 3 Q26
26 \(\text{g}(x) = 16 - x \qquad \text{h}(x) = x^3\)
Solve \(\quad \text{gh}(x) = 24\) [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(16 - x^3\) | M1 | |
| \(x^3 = 16 - 24\) or \(x^3 = -8\) or \(x = \sqrt[3]{-8}\) or \(-x^3 = 24 - 16\) or \(-x^3 = 8\) or \(-x = -\sqrt[3]{-8}\) | M1dep | |
| \(-2\) | A1 |
Additional guidance
| \(16 - x^3 = 24 \quad x^3 = 24 - 16\) | M1M0A0 |