Higher June 2019 Paper 3 Q8
8 Rearrange \(\quad y = 3x - 2 \quad\) to make \(x\) the subject.
Circle your answer. [1 mark]
- \(x = \dfrac{y}{3} - 2\)
- \(x = \dfrac{y + 2}{3}\)
- \(x = \dfrac{y - 2}{3}\)
- \(x = \dfrac{y}{3} + 2\)
| Answer | Mark | Comments |
|---|---|---|
| \(x = \dfrac{y + 2}{3}\) | B1 |