Higher November 2019 Paper 2 Q15
15 Rearrange \(\quad y = \sqrt{w^3} \quad\) to make \(w\) the subject.
Circle your answer. [1 mark]
- \(w = y^6\)
- \(w = \sqrt[3]{y^2}\)
- \(w = \sqrt{y^3}\)
- \(w = y^5\)
| Answer | Mark | Comments |
|---|---|---|
| \(w = \sqrt[3]{y^2}\) | B1 |
15 Rearrange \(\quad y = \sqrt{w^3} \quad\) to make \(w\) the subject.
Circle your answer. [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| \(w = \sqrt[3]{y^2}\) | B1 |